Question

Find the equation of the circle passes the following three

points?
a) (1,0) (0,1) and (2, 2)​

Answer 1

we have:(x, y1)=(1,0)

(x2,y2)=(0,1)

then the equation of circle is

(x-1)(x-x2)+(y-y1)(y-y2)=0

=(x-1)(x-0)+(y-0)(y-1)=0

=x2-x+y2-y=0

=x2++y2-x-y=0.

Hence this is the answer.

Answer 2

2.2

Explanation:

the equation was not the only way that could change in a single year of growth