Question

An electric circuit, powered by a voltage of 100 V, absorbs a power of 4.41 kW; calculate the intensity of the current that runs through the circuit and the energy absorbed by it in 2 hours and 15 minute​

Answer 1

I = 44.1[amp]

P = 9.92 [kw-hr]

Step-by-step explanation:

We know that electrical power can be calculated by means of the following expression.

`P=V*I`

where:

P = power = 4.41 [kW] = 4410 [w]

V = 100 [V]

I = current [amp]

Now we have:

`I=P/V\\I = 4410/100\\I = 44.1 [amp]`

Now the power absorbed during this time is equal to the product of power by time.

`15[min]*(1hr)/(60min) =0.25 [hr]`

t = time = 2.25 [hr]

`P_(ab)=4.41*2.25\\P=9.92[kW-hr]`