Answer:
Equation of line in Point Slope Form is
![\mathbf{y-2=-2(x-9)}](https://img.qammunity.org/2021/formulas/mathematics/college/tkvhu8tzjqnijxssi4x3zk7xv6n02ku7dx.png)
Equation of line in Slope Intercept Form is:
![\mathbf{y=-2x+20}](https://img.qammunity.org/2021/formulas/mathematics/college/x4jy30loul16cyb9mbf639dwbqcjyfooko.png)
Explanation:
We need to write equation of line having slope -2 and point (9,2)
a) Equation in Point Slope Form
The general equation of point slope form is:
![y-y_1=m(x-x_1)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/ks7lzc9jj3emt3ptrdvrvr0uzhz4c0qyo5.png)
Where x₁ and y₁ are the points of line and m is slope.
x₁=9 and y₁=2 and m=-2
Putting values in formula and finding equation:
![y-y_1=m(x-x_1)\\y-2=-2(x-9)](https://img.qammunity.org/2021/formulas/mathematics/college/dcpqnasuks198njfpin59ag9hfvpatimin.png)
So, Equation of line in Point Slope Form is
![\mathbf{y-2=-2(x-9)}](https://img.qammunity.org/2021/formulas/mathematics/college/tkvhu8tzjqnijxssi4x3zk7xv6n02ku7dx.png)
b) Equation in Slope Intercept Form
The general equation of Slope Intercept Form is:
![y=mx+b](https://img.qammunity.org/2021/formulas/mathematics/middle-school/yj5waqmoy4i54laybzhhshd88hyo5w5rj5.png)
where m is slope and b is y-intercept
Finding y-intercept using slope m=-2 and point(9,2)
![y=mx+b\\2=-2(9)+b\\2=-18+b\\b=2+18\\b=20](https://img.qammunity.org/2021/formulas/mathematics/college/41jmck9bfko6l340dmnzvijumq9t6mafi2.png)
The equation in slope m=-2 and b=20 is:
![y=mx+b\\y=-2x+20](https://img.qammunity.org/2021/formulas/mathematics/college/sccjkgcrjyr3wm4vbagqnneuh0b9ehtaem.png)
So, equation of line in Slope Intercept Form is:
![\mathbf{y=-2x+20}](https://img.qammunity.org/2021/formulas/mathematics/college/x4jy30loul16cyb9mbf639dwbqcjyfooko.png)