Question

Find the horizontal [A] and vertical [B] components of the given vector. Round to four places.

Answer 1

• The equation of the horizontal component is:

`v_x=v\:cos\:\theta \:`

`=-10.7294`

• The vertical component will be:

`v_y=v\:sin\:\theta \:\:`

`=-16.5218`

Explanation:

Let 'v' be the vector

The equation of the horizontal component is:

`v_x=v\:cos\:\theta \:`

The equation of the vertical component is:

`v_y=v\:sin\:\theta \:\:`

• The magnitude of a vector 'v' is expressed as 'v'.

As

• Magnitude = v = 19.7

• Ф = 237°

The horizontal component will be:

`v_x=v\:cos\:\theta \:`

`=\left(19.7\right)\cos \left(237^(\circ \:)\right)`

`=-10.7294`

The vertical component will be:

`v_y=v\:sin\:\theta \:\:`

`=19.7\sin \:\left(237^(\circ \:\:)\right)`

`=-16.5218`