Question

B is the midpoint of AC and D is the midpoint of CE. Solve for x,

given BD - 3x + 3 and AE = 5x + 11.
PLEASE HELP FOR GEOMETRY

Answer 1

Explanation:

Required Answer:-

ATQ

`{:}\longrightarrow`
`\sf 2BD=AE`

`{:}\longrightarrow`
`\sf 2 (-3x+3)=5x+11`

`{:}\longrightarrow`
`\sf -6x+6=5x+11`

`{:}\longrightarrow`
`\sf -6x-5x=11-6`

`{:}\longrightarrow`
`\sf -11x=5`

`{:}\longrightarrow`
`\sf x={\frac {5}{-11}}`

Answer 2

9514 1404 393

Answer:

x = 5

Explanation:

Midline BD is half the length of base AE, so we have ...

2BD = AE

2(3x +3) = 5x +11

6x +6 = 5x +11 . . . eliminate parentheses

x = 5 . . . . . . . . . subtract 5x+6