Answer:
The required heat flux = 12682.268 W/m²
Step-by-step explanation:
From the given information:
The initial = 25°C
The final = 75°C
The volume of the fluid = 0.2 m/s
The diameter of the steel tube = 12.7 mm = 0.0127 m
The fluid properties for density
= 1000 kg/m³
The mass flow rate of the fluid can be calculated as:
![m = pAV](https://img.qammunity.org/2021/formulas/engineering/college/1jq2oila29rcetfapvsriuwadtj7hpqwpr.png)
![m = \rho (\pi)/(4)D^2V](https://img.qammunity.org/2021/formulas/engineering/college/qk365ybu70nschwtq5306kvzlh9tpvlwbu.png)
![m = 1000 * (\pi)/(4) * ( 0.0127)^2 * 0.2](https://img.qammunity.org/2021/formulas/engineering/college/z844dz0lvvb8jur74lxfnfogf785s5mlan.png)
![m = 0.0253 \ kg/s](https://img.qammunity.org/2021/formulas/engineering/college/tfrdr3vratlj4z7nl0y2cwb2tfkwgptm4i.png)
To estimate the amount of the heat by using the expression:
![q = mc_p(T_(final)-T_(initial))](https://img.qammunity.org/2021/formulas/engineering/college/rik1wpy2arktw9rdqgb0p821j209f9zviq.png)
q = 0.0253 × 4000(75-25)
q = 101.2 (50)
q = 5060 W
Finally, the required heat of the flux is determined by using the formula:
![q](https://img.qammunity.org/2021/formulas/engineering/college/pjrk342rr3vbj1q7hsx38mjp5jzq21v7ff.png)
![q](https://img.qammunity.org/2021/formulas/engineering/college/rt6om4seqyegdiucqmldpcs3ce8egvz7sg.png)
![q](https://img.qammunity.org/2021/formulas/engineering/college/nw1nfp578tznihidcvfrljgnrgmmwz43xc.png)
q" = 12682.268 W/m²
The required heat flux = 12682.268 W/m²