48.8k views
1 vote
A balloon contains 146.0mL of gas confined at a pressure of 1.30atm and a temperature of 5.00ºC. If the pressure changes to 2.60 atm and the temperature decreases to 2.00ºC, what will be the volume of gas in the balloon?

User Vit Ias
by
5.3k points

1 Answer

4 votes

Answer:

V₂ = 72.2 mL

Step-by-step explanation:

Given data:

Initial volume = 146.0 mL

Initial pressure = 1.30 atm

Initial temperature = 5.00 °C (5.00 +273 = 278 K)

Final temperature = 2.00 °C ( 2.00+273 = 275 K)

Final volume = ?

Final pressure = 2.60 atm

Formula:

P₁V₁/T₁ = P₂V₂/T₂

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

Solution:

P₁V₁/T₁ = P₂V₂/T₂

V₂ = P₁V₁T₂ /T₁P₂

V₂ = 1.30 atm × 146.0 mL × 275 K / 278K × 2.60 atm

V₂ = 52195 atm .mL. K / 722.8 K.atm

V₂ = 72.2 mL

User Vonqo
by
5.4k points