Answer:
AE:
![√(15300)](https://img.qammunity.org/2021/formulas/mathematics/high-school/dgk8er2q3kkiihcwrn7sxcdtea181m4lnx.png)
DE:150
PABCDE: 720
Explanation:
We can find AE by the pythagorean theorem,
![a^(2)+b^(2)=c^(2)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/wps9fo3b4w26yqm8cwk32he0gvppf7n6m5.png)
AE is the hypotenuse so AE=c, and the leg of the triangle would be 150-30=120
![50^(2)+120^(2)=c^(2)](https://img.qammunity.org/2021/formulas/mathematics/high-school/z0vc53tzmsbl09h4ru4cseaxeu78ai08h7.png)
c^2=2500+14400
AE=130
We can use the pythagorean theorem again to find DE.
The base would equal 140-50=90 and the height would equal 120
![90^(2) +120^(2) =DE^(2)](https://img.qammunity.org/2021/formulas/mathematics/high-school/51hauv7b0b4jsib4sbnc79ob79m4csmj0p.png)
DE^2=22500
DE=150
The perimeter would be 150+140+150+130+150=720
Let me know if somethings wrong