The roots of 3x^2+kx+12=0 are equal, find k.

asked Mar 26, 2021 30.1k views

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2 votes

Answer:

k = 12

Explanation:

3(x² + kx + 2²) = 3(x² + ____x + 4) = 3(x² + 4x + 4) = 3x² + 12x + 12 ⇒ k = 12

Shinese answered Mar 27, 2021

6.4k points

4 votes

Answer:

Explanation:

3x^2+kx+12=0

k= -3x-12/x

Dave Forgac answered Mar 30, 2021

5.7k points

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