Question

A solution of copper sulfate (CuSO4) produced by bioleaching has a concentration of 0.319 g/dm3 Relative atomic masses (Ar): Cu = 63.5 O = 16 S = 32 Calculate the number of moles of copper that can be produced from 1 dm3 of this solution.

Answer 1

moles Cu produced : 0.002

Further explanation

Concentration of copper sulfate (CuSO₄) : 0.319 g/dm³

MW CuSO₄ :

`\tt =63.5+32+4* 16=159.5~g/mol`

mol CuSO₄ /dm³ :

`\tt (0.319)/(159.5)=0.002`

CuSO₄⇒Cu²⁺ + SO₄²⁻

mol Cu : mol CuSO₄ = 1 : 1 , so mol Cu²⁺=0.002