Question

A particle moves along a straight line with the equation of motion s = t^{5} - 2 t^{4} Find the value of t (other than 0 ) at which the acceleration is equal to zero.

Answer 1

t = 8/5

Explanation:

I'm assuming the equation given is the velocity of the particle

Derive the equation

`5t^4 - 8t^3`

Set it equal to 0 & solve for t

`0 = 5t^4 - 8t^3\\8t^3 = 5t^4\\8 = 5t\\(8)/(5) = t`