Question

Find the wavelength of light that has its third minimum at an angle of 48.6º when it falls on a single slit of width 3.00 μm .

Answer 1

750 nm

Step-by-step explanation:

It is given that,

Third minimum is at an angle of 48.6º when it falls on a single slit of width 3.00 μm.

We need to find the wavelength of the light. For a single slit experiment, the relation between wavelength and slit width is given by :

`d\sin\theta=n\lambda`

For third minimum, n = 3

`\lambda=(d\sin\theta)/(n)\\\\\lambda=(3\cdot10^(-6)\cdot\sin48.6)/(3)\\\\\lambda=7.5* 10^(-7)\ m\\\\\lambda=750\ nm`

So, the wavelength of light is 750 nm.