Question

If the initial oscillation of the pendulum has an amplitude of 2.5m , what is the amplitude d of oscillation after 20 s ?

Answer 1

The value is
`y = 0.0458 \ m`

Step-by-step explanation:

From the question we are told that

The initial amplitude is A = 2.5 \ m

The time considered is t = 20 s

Generally the amplitude at time t is mathematically represented as

`y = Ae^{- (t)/(\tau) }`

Here
`\tau` is the time constant let assume the value to be
`\tau = 5 \ s`

So

`y = 2.5 * e^{- (20)/(5) }`

=>
`y = 0.0458 \ m`