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Please HELP!! GEOMETRY 20 points!!

A triangle has sides of lengths a=38,
b=58, c=73 km.

Find the measures of the 3 angles.

Enter your answer as a number;
answer should be accurate to 2
decimal places.

Angle A = ?
Angle B = ?
Angle C= ?

User Nwe
by
8.2k points

1 Answer

9 votes

a = 38

b = 58

c = 73

[use the Law of Cosines]

cos(A) = b² + c² - a² / 2bc

cos(B) = c² + a² - b ² / 2ca

cos(C) = a² + b² - c² / 2ab

[substitute the values]

∡A = 52.09

∡B = 31.12

∡C = 96.79

User Kevin Schmid
by
8.6k points

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