Question

Pls answer seriouslyyy thank u

Answer 1

See Explanation

Explanation:

3.

XY is tangent at P and CP is radius

`\therefore CP\perp XP\\(\because tangent\: is \: perpendicular \: to\: radius) \\\\</p><p>\therefore m\angle CPX = 90\degree \\`

4.

Radius of the circle = diameter /2 = 13/2 = 6.5.cm

5.

For BD to be be tangent to the circle with center C, BD should make right angle with radius CB.

`AD^2` should be equal to the sum of the squares BD and AB.

Let us work it out:

`AD^2 = 7^2 = 49....(1)\\</p><p>AB^2 + BD^2 = 5^2 +5^2 \\</p><p>AB^2 + BD^2 = 25 + 25 \\</p><p>AB^2 + BD^2 = 50....(2) \\`

From equations (1) & (2), it is obvious that:

`AD^2 \\eq AB^2 + BD^2`

So, BD is not tangent to the
`\odot\: C.`

6.

Tangents drawn from an external point to a circle are congruent.

In circle with center C, BA and BD are tangents drawn from external point B.

Therefore,

BA = BD

x = 4

7.

In circle with center C, BA and BD are tangents drawn from external point B.

Therefore,

BD = BA (tangents drawn from external point to a circle)

x = 2

8.

In circle with center C, BA and BD are tangents drawn from external point B.

Therefore,

BA = BD (tangents drawn from external point to a circle)

2x = 10

x = 10/2

x = 5