Question

Suppose (ideally) a hammer claw moves a distance of 0.10 meters to remove a nail. If a resistance force of 1500 N is exerted by the claw, and you move the handle of the hammer 0.5 meters, what is the effort force?

Answer 1

7500 N

Explanation:

Given that,

A hammer claw moves a distance of 0.10 meters to remove a nail.

Resistance force, F = 1500 N

The person move the handle of the hammer 0.5 m

We need to find the effort force. Let it is F'. The mechanical advantage is given by :

`m=(effort)/(resistance)=(d_i)/(d_o)`

Where
`d_i\ \text{and}\ d_o` are input and output distance respectively.

`m=(F')/(F)=(0.1)/(0.5)\\\\(1500)/(F)=(0.1)/(0.5)\\\\(1500)/(F)=0.2\\\\F=7500\ N`

So, the effort force is 7500 N.