Find the value of :x^2+2xy+y^2-3x-3y-1 have: x^2-y=y^2-x (x\\eqy)

asked May 18, 2021 26.6k views

3 votes

Find the value of :x^2+2xy+y^2-3x-3y-1
have: x^2-y=y^2-x (x
$\\eq$ y)

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5 votes

Answer: The answer is x^2+2xy+2y^2–3x–3y–1

Step-by-step explanation: Move 2 to the left of y^2.

Sabbane answered May 24, 2021

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