Question

A ball is thrown with initial velocity 20 meter per second by making an angle 30 degree with a horizontal then find time of flight.

Answer 1

`\huge\boxed{\sf T = 2.04\ secs}`

Step-by-step explanation:

Given Data:

Initial Velocity =
`\sf V_(i)` = 20 m/s

Angle =
`\sf \theta` = 30°

Acceleration due to gravity = g = 9.8 m/s²

Required:

Time of flight = T = ?

Formula:

`\sf T = (2\ V_(i)\ sin\theta)/(g)`

Solution:

Putting values in the above formula

T = 2(20)sin 30 / 9.8

T = 40 (0.5) / 9.8

T = 20 / 9.8

T = 2.04 secs

`\rule[225]{225}{2}`

Hope this helped!

~AnonymousHelper1807