Question

A sample of vinegar containing 0.100 mol of ethanoic acid has a concentration of 0.125M of ethanoic acid. What is the volume of the solution.

Answer 1

0.8 L

Step-by-step explanation:

We are given:

Molarity of Ethanoic Acid in vinegar = 0.125 M

Number of moles of Ethanoic Acid = 0.1 mole

Finding the volume of the solution:

We know that the molarity of a solution is defined as:

Molarity = n / V (where n is the number of moles and V is the volume in L)

replacing the variables with the given values:

0.125 = 0.1 / V

Multiplying by V on both the sides

0.125V = 0.1

Dividing both sides by 0.125

V = 0.1 / 0.125

V = 0.8 L

Therefore, the volume of the solution is 0.8 L