Question

Solve the quadratic equation and give both solutions.

14x^2 − 29x − 15 = 0

Answer 1

Explanation:

`x_(1,\:2)=(-\left(-29\right)\pm √(\left(-29\right)^2-4\cdot \:14\left(-15\right)))/(2\cdot \:14)` so
`x=(5)/(2)`
`x=-(3)/(7)`