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the first and last term arithmetic sequence are 9 and 165 respectively.if the sum of all the terms of the arithmetic sequence is 3480,find the number of terms and the common difference of this arithmetic sequence​

2 Answers

4 votes

Answer:

Required Answer:-

  • first term =a=9
  • Last term =l=165
  • Sn=3480

As we know that in a AP


{:}\longrightarrow
\sf S_n={\frac {1}{2}}(a+l)n

  • Substitute the values


{:}\longrightarrow
\sf 3480={\frac {1}{2}} (9+165)n


{:}\longrightarrow
\sf 3480={\frac {1}{2}}(174)n


{:}\longrightarrow
\sf 3480={\frac {174}{2}}n


{:}\longrightarrow
\sf 3480=87n


{:}\longrightarrow
\sf n={\frac {3480}{87}}


{:}\longrightarrow
\sf n=40


\thereforeNumber of terms=40.

User Splrs
by
4.6k points
2 votes

Answer:

  • 40 terms

Explanation:

Sum of n terms formula:

  • Sn = 1/2n(a1 + an)

Solving for n

  • 3480 = 1/2n(9 + 165)
  • 3480 = 87n
  • n = 3480/87
  • n = 40
User Goliatone
by
5.0k points