Question

Question 3. Starting with acetylene

, devise a scheme to prepare 1-chloroheptanol
. There is more
than one way to complete this synthesis
. It can be completed in as few as three reactions. You
can use any alkyl halides as needed as sources of carbon atoms. PLEASE EXPLAIN THE PROCESS. I’m begging. Please.

Answer 1

See explanation and image attached

Step-by-step explanation:

Starting from acetylene, we can react the substrate with methyl iodide in the presence of sodamide and ammonia. We then obtain propyne which then undergoes a similar reaction using butyl iodide to yield 2-heptyne.

This may now be reduced using hydrogen and platinum to yield heptane. Heptane is chlorinated in the presence of light to yield a mixture of products of which 1-chloroheptane is one.