Question

Determine the equation of the line that is parallel to the given

line, through the given point.
y = 3x - 4; (2, -3)

Answer 1

y=3x-9

Explanation:

Since it's parallel the slope has to be the same. The intercept is found by inserting the x and y into the new equation:

-3=3(2)+b

-3=6+b

Subtract 6 from both sides.

-9=b

This gives all parts to the answer,

y=3x-9

You could also check your work by graphing the point and using the slope of 3x until you get to the y-intercept.

Answer 2

y = 3x - 3

Given:

y = 3x - 4

through (2, 3)

To Find:

equation of the line parallel to y = 3x - 4 through the given point (2, -3)

Explanation:

y = mx + b

The line is parallel, so the slope is the same

y = 3x + b

Plug in the x and y values of your point

-3 = 3(2) + b

Solve for 'b'

-3 = 6 + b

0 = b + 3

b = -3

Your final equation is,

y = 3x - 3