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You have a bottle of silver nitrate (AgNO3) that is labeled 500 g. How many moles of silver nitrate is that? Please show ALL WORK

User Cloudy
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1 Answer

7 votes

Answer:

2.94 mol

Step-by-step explanation:

Ag- 107.9g N- 14g O- 16g ---> AgNO3- 169.9g

500g x 1 mol (AgNO3)/ 169.9g (AgNO3) = 500/169.9 = 2.94 mol silver nitrate

User Azriz
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