Question

A diver is on a board 1.80 m above

the water. She jumps straight up
at 3.62 m/s.
At what speed does she hit the water?
[?] m/s

Answer 1

v = 6.95 m/s

Step-by-step explanation:

Given that,

A diver is on a board 1.80 m above the water, s = 1.8 m

The initial speed of the diver, u = 3.62 m/s

Let v is the speed with which she hit the water. It will move under the action of gravity. Using the equation of motion as follows :

`v^2-u^2=2gs\\\\v=√(u^2+2gs) \\\\v=√((3.62)^2+2(9.8)(1.8)) \\\\v=6.95\ m/s`

So, she will hit the water with a speed of 6.95 m/s.