Question

What is the solution to the system of equations below?

y=-6x-10
and
y=-3x-21
(2, -22)
(2,48)
(-2, 2)
(-2, -20)

Answer 1

A. (2, -22)

Explanation:

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Answer 2

Please check the explanation.

Explanation:

Given the equations

`y=-6x-10`

`y=-3x-21`

solving the system of the equations

Arrange the equation variables for elimination

`\begin{bmatrix}y+6x=-10\\ y+3x=-21\end{bmatrix}`

`y+3x=-21`

`-`

`\underline{y+6x=-10}`

`-3x=-11`

`\begin{bmatrix}y+6x=-10\\ -3x=-11\end{bmatrix}`

solve

`-3x=-11`

Divide both sides by -3

`(-3x)/(-3)=(-11)/(-3)`

`x=(11)/(3)`

`\mathrm{For\:}y+6x=-10\mathrm{\:plug\:in\:}x=(11)/(3)`

`y+6\cdot (11)/(3)=-10`

`y+6\cdot (11)/(3)=-10`

`y=-32`

Therefore, the solutions to the system of the equations are:

`y=-32,\:x=(11)/(3)`

But, it seems none of the options is true.