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(04.04 LC)

On a coordinate grid, point T is at (2,-4) and point Sis at (2,6). The distance (in units) between points T and Sis
numbers, such as 2.) (5 points)
(Input only whole

User Kuvalya
by
7.8k points

2 Answers

3 votes

Answer:

t and s

Explanation:

User Jesbus
by
8.3k points
5 votes

Answer:

The distance 'd' between T and S:


  • d=10

Explanation:

As the point 'T' is located at (2, -4)

  • So, the point 'T' has the coordinates (2, -4)

And the point 'S' is located at (2, 6)

  • So, the point 'T' has the coordinates (2, 6)

The distance 'd' between T and S can be computed using the formula:


d=√(\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2)


=√(\left(2-2\right)^2+\left(6-\left(-4\right)\right)^2)


=√(\left(2-2\right)^2+\left(6+4\right)^2)


=√(0+10^2)


=√(10^2)


d=10

Therefore, the distance 'd' between T and S:


  • d=10
User Stevekohls
by
8.1k points

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