Question

Helppp quick pointsss

Answer 1

1) The angle would be 150 degrees

a) coordinates would be (
`-(√(3))/(2)`,
`(1)/(2)` )

b) Trigonometric ratios:

sin:
`(1)/(2)`

cos:
`-(√(3))/(2)`

tan:
`-(√(3))/(3)`

csc: 2,

sec:
`-(2√(3))/(3)`

cot:
`√(3)`

Step-by-step explanation:

`(17\pi )/(6)` simplifys to
`(5\pi )/(6)` which has a reference angle of
`(\pi )/(6)`. We can take the coordinates of
`(\pi )/(6)` and make the x value negative to find the correct coordiantes. Then, using those coordinates, plug the into the trigonomic equations.

For example, sin in opposite/hypotenuse. So sin = 1/2 divided by 1. Then you can find the rest of the equations that way.

cos= adjacent/hypotenuse

tan= sin/cos

csc= hypotenuse/opposite

sec= hypotenuse/adjacent

cot= cos/sin