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How many 5-digit personal identification numbers are possible if the number cannot contain a

zero?

1 Answer

3 votes

Answer:

59049 digits

Explanation:

Given

Digits = 0 to 9

Required

Determine number of 5 digit pins that must not contain 0

There are 10 digits.

Since the pin must not contain 0, there are 9 digits left to select from.

The question didn't state that a digit can not be repeated, so I'll assume that repetition of digit is allowed.

The 1st digit of the 5 could be any of the 9 digits

The 2nd could be any of the 9 digits

The 3rd could be any of the 9 digits

The 4th could be any of the 9 digits

The 5th could be any of the 9 digits

Hence, number of selection is calculated as this:

Selection = 9 * 9 * 9 * 9 * 9

Selection = 59049

User Himanshu Likhyani
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