Question

32,500 joules are used to boil a sample of water at its melting point what is the mass of the water?

Answer 1

43.18 gm

Step-by-step explanation:

Heat of fusion of water at 0° C is 334 j/gm

then you have to heat the water to boiling point (100 C)

specific heat of water is 4.186 j/g-c

x = grams of water

x ( 334 + 4.186 (100) ) = 32500

x = 43.18 gm