Question

two points a(2 "-4)" and b (-6 4) are given. p is the midpoint of l the line segment AB. Find the equation of the straight line with the slope of 3 passing through P

Answer 1

Answer: y=3x+6

Explanation:

`\text{mdpt}_{\overline{AB}}=\left((2-6)/(2), (-4-4)/(2) \right)=(-2, 0)`

So, the equation of the line is:

`y=3(x+2)\\y=\boxed{3x+6}`