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If the weight of an object on the moon is 1/6 of the weight of an object on earth. What

would be the weight of an object on the moon who has the weight of 4800 N on earth?

User Zmirc
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2 Answers

1 vote

Answer:

1200 N

Step-by-step explanation:

User Brian Tracy
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3 votes

Answer:

1200N

Step-by-step explanation:

Suppose a body of mass "m" and its weight on the moon is Wm (where W is the weight and "m" is the moon ;which means weight on the moon).Mass of the moon is "M"

and its radius is "R"

Weight of an object on the moon = "F"(Force)with which the moon pulls.

Wm = GM*m/r2

Weight of the same object on the earth is We(where W is the weight and "e" is the earth; which means weight on the earth).

Mass of the earth is 100 times of that of the moon.

Radius of the moon = R

Radius of the Earth = 4R

Weight of the object on the moon =

We = G100M*m/(4R)2(Pronounced 4 R square)

We = G100M*m/(16R)2(Pronounced 16 R square)

Wm/We = G * M * m * 16R2/R2 * g * 100M * m

=16/100

Therefore, 4800N on earth= 1200N on moon

User Ahsan Farooq
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