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How many 5-digit numbers are there in which three of the digits are 6, or two of

the digits are 9 ?

User Orka
by
8.5k points

1 Answer

0 votes

Answer:

The value is
Z = 80

Explanation:

From the question we are told that

The total number of digit is n = 5

The total possible number of 6 is k = 3

The total possible number of 9 is a = 2

Generally the number of way of representing a 5 digits number(i.e the number of five digit numbers ) in which 3 of the digit are 6 is mathematically represented as


N = ^ nP_k

Here P stands for permutation hence we are going to be making use of the permutation function in our calculators


N = ^ 5P_3

=>
N = 60

Generally the number of way of representing a 5 digits number(i.e the number of five digit numbers ) in which 2 of the digit are 9 is mathematically represented as


M = ^ nP_a


M = ^ 5P_2

=>
M = 20

Generally the number of 5-digit numbers there are in which three of the digits are 6, or two of the digits are 9 is mathematically represented as


Z = M + N

=>
Z = 60 + 20

=>
Z = 80

User Obelia
by
7.9k points

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