Question

13. How many moles of sodium hydroxide are needed to neutralize 50grams of sulfuric acid?

2NaOH H2SO4 → Na2SO4 + 2H2O

Answer 1

1.02mole

Step-by-step explanation:

The reaction equation is given as:

2NaOH + H₂SO₄ → Na₂SO₄ + 2H₂O

Given:

Mass of H₂SO₄ = 50g

Unknown:

Number of moles of NaOH = ?

Solution:

To solve this problem, we first find the number of moles of the acid given;

Number of moles =
`(mass)/(molar mass)`

Molar mass of H₂SO₄ = 2(1) + 32 + 4(16) = 98g/mol

Now;

Number of moles =
`(50)/(98)` = 0.51mole

From the balanced reaction equation:

1 mole of H₂SO₄ will be neutralized by 2 mole of NaOH

0.51 mole of H₂SO₄ will be neutralized by 2 x 0.51 = 1.02mole of NaOH