Question

How much would a spring scale with k = 120 N/m stretch, if it had a 3.75 J of work done
on it?

Answer 1

0.25m

Step-by-step explanation:

Given parameters:

Spring constant , K = 120N/m

Work done = 3.75J

Unknown:

magnitude of extension = ?

Solution:

To solve this problem;

Work done =
`(1)/(2)`kx²

K is the spring constant

x is the extension

3.75 =
`(1)/(2)` x 120x²

3.75 = 60x²

x² = 0.06

x = √0.06 = 0.25m