Question

A 2.0 sample of N2 occupy 50.0L at 15 degrees Celsius and 640mmHg. What volume will the gas occupy at 45 degrees Celsius and 160mmHg?

Answer 1

220.8L

Step-by-step explanation:

Given parameters:

Initial volume = 50L

Initial temperature = 15°C = 288K

Initial pressure = 640mmHg

Final temperature = 45°C = 318K

Final pressure = 160mmHg

Unknown:

Final volume = ?

Solution:

Using the combined law;

`(p_(1)v_(1) )/(T_(1) )` =
`(p_(2)v_(2) )/(T_(2) )`

p,v and T are pressure, volume and Temperature

`(640 x 50)/(288)` =
`(160 x v_(2) )/(318)`

160 x 288 x v₂ = 640 x 50 x 318

v₂ = 220.8L