476,229 views
22 votes
22 votes

\sqrt[3]{x}=\sqrt[5]{32}

why can't i just cube both sides, therefore kick the x out of the cubic root, and then i would have

x = √(32) \\then \\x = √(16 * 2)\\x = 4√(2)

User Gonzalo Contento
by
3.0k points

1 Answer

15 votes
15 votes

Answer:


x = 8

Explanation:


{x}^{ (1)/(3) } = {32}^{ (1)/(5) }


{( {x}^{ (1)/(3) } )}^(3) = {( {32}^{ (1)/(5) } )}^(3)


{x}^(1) = \sqrt[5]{ {32}^(3) }


x = \sqrt[5]{32768}


x = 8

User Goofball
by
2.5k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.