Question

A new drug on the market is known to cure 30% of patients with cervical cancer. If a group of 18 patients is randomly selected, what is the probability of observing, at most, one patient who will be cured of cervical cancer?

Answer 1

Probability cured of cervical cancer = 18C0 (0.30)⁰(0.70)¹⁸ + 18C1(0.30)(0.70)¹⁷

Explanation:

Given:

Patients cured = 30% = 0.30

Number of patients (n) = 18

Probability cured of cervical cancer = P(X≤1)

Probability cured of cervical cancer = P(X=0) + P(X=1)

Probability cured of cervical cancer = 18C0 (0.30)⁰(0.70)¹⁸ + 18C1(0.30)(0.70)¹⁷