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Desperate for helllppp pls

Desperate for helllppp pls-example-1
User Theozaurus
by
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1 Answer

11 votes

Answer:

  • B) - 1 < x < - 0.2

Explanation:

Given inequality

  • |5x + 3| < 2

The LHS is absolute value so we look at two options:

Option 1

5x + 3 is positive, then the inequality becomes:

  • 5x + 3 < 2
  • 5x < 2 - 3
  • 5x < - 1
  • x < - 1/5 or x < - 0.2

Option 2

5x + 3 is negative, then the inequality becomes:

  • - (5x + 3) < 2
  • 5x + 3 > - 2
  • 5x > - 2 - 3
  • 5x > - 5
  • x > - 1

The solution is the combination of the two intervals:

  • x > - 1 and x < - 0.2 ⇒ - 1 < x < - 0.2

Correct choice is B

User Ktilcu
by
9.0k points

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