Question

Which of the following quadratic equations has no real solution?

A) x^2-6x-2=0
B) 4x^2+4x+1=0
C) x^2+3x-5=0
D) 2x^2-4x+3=0

Answer 1

D. You define if a quadratic equation has an answer or not by the delta (the calculation inside the sqrt on the quadratic formula). So you simply calculate b^2 -4ac, if the answer is equal or greater than zero there is a solution, if not there isn’t. (Consider ax^2+bx+c) Hope it helped :)