Question

A pot of water at 20.0ºC is warmed to 100º when 40000cal is added. what is the mass of the water?

Answer 1

500 g

Step-by-step explanation:

m = Mass of water

c = Specific heat of water =
`1\ \text{cal/g}^(\circ)\text{C}`

`\Delta T` = Temperature difference =
`100-20=80^(\circ)\text{C}`

Q = Heat added = 40000 cal

Heat is given by

`Q=mc\Delta T\\\Rightarrow m=(Q)/(c\Delta T)\\\Rightarrow m=(40000)/(1* 80)\\\Rightarrow m=500\ \text{g}`

The mass of water is 500 g.