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If the function y = 2x2 + 3x has the domain (-2,-1,0}, what is its range?

User CheeHow
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1 Answer

5 votes

Answer:

(- 2, - 1, 0 )

Explanation:

to find the range (values of y ) substitute the values of x from the domain.

x = - 2 : y = 2(- 2)² + 3(- 2) = 2(4) - 6 = 8 - 6 = 2

x = - 1 : y = 2(- 1)² + 3(- 1) = 2(1) - 3 = 2 - 3 = - 1

x = 0 : y = 2(0)² + 3(0) = 0 + 0 = 0

range is (- 2, - 1, 0 )

User Marylu
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