Question

PLEASEEEE HELPPP MEEE
6 and 7 PLEASE

Answer 1

Question 6

`\left(5a+2\right)\left(a+4\right)=\:5a^2+22a+8`

Question 7

The width is 2x.

Explanation:

Question 6)

Expand

`(5a+2)(a+4)`

solving to the expand

`(5a+2)(a+4)`

• 
  `\mathrm{Apply\:FOIL\:method}:\quad \left(a+b\right)\left(c+d\right)=ac+ad+bc+bd`

`a=5a,\:b=2,\:c=a,\:d=4`

so the expression becomes

`=5aa+5a\cdot \:4+2a+2\cdot \:4`

`=5aa+5\cdot \:4a+2a+2\cdot \:4`

`=5a^2+20a+2a+8`

adding similar elements: 20a+2a=22a

`=5a^2+22a+8`

Hence,

`\left(5a+2\right)\left(a+4\right)=\:5a^2+22a+8`

Question 7)

Given

• 
  `A\:=\:8x^2`

• 
  `l=4x`

Using the formula

width = Area/Length

`=\:(8x^2)/(4x)`

`=2x` ∵
`\mathrm{Divide\:the\:numbers:}\:(8)/(4)=2`

Therefore, the width is 2x.