Question

Need help, will give 100 points

Answer 1

Already answered on the other one

Explanation:

Answer 2

• f(x)=2x²-x
• g(x)=x+1

#1

`\\ \rm\Rrightarrow (gof)(-1)`

`\\ \rm\Rrightarrow g(f(-1))`

`\\ \rm\Rrightarrow g(2(-1)^2-(-1))`

`\\ \rm\Rrightarrow g(2+1)`

`\\ \rm\Rrightarrow g(3)`

`\\ \rm\Rrightarrow 3+1`

`\\ \rm\Rrightarrow 4`

#2

`\\ \rm\Rrightarrow (fog)(-1)`

`\\ \rm\Rrightarrow f(g(-1))`

`\\ \rm\Rrightarrow f(-1+1)`

`\\ \rm\Rrightarrow f(0)`

`\\ \rm\Rrightarrow 2(0)^2-0`

`\\ \rm\Rrightarrow 0`

#3

`\\ \rm\Rrightarrow (gof)(x)`

`\\ \rm\Rrightarrow g(f(x))`

`\\ \rm\Rrightarrow g(2x^2-x)`

`\\ \rm\Rrightarrow 2x^2-x+1`

#4

`\\ \rm\Rrightarrow (fog)(x)`

`\\ \rm\Rrightarrow 2(x+1)^2-x`

`\\ \rm\Rrightarrow 2(x^2+2x+1)-x`

`\\ \rm\Rrightarrow 2x^2+4x+2-x`

`\\ \rm\Rrightarrow 2x^2+3x+2`

#5

No they are not equal