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The length of Rectangle 1 is 3.2 x 10^5 m. The width of Rectangle 1 is 1.6 x 10^4 m. What is the area of Rectangle 1? Write the answer in Scientific Notation.


Find the area of Rectangle 2 if its length is 1.28 x 10^7 m and its width is 8 x 10^3 m. Write the answer in Scientific Notation.


How many times larger is the area of Rectangle 2 than the area of Rectangle 1? Write the answer in Scientific Notation.


How many times larger is the area of Rectangle 2 than the area of Rectangle 1? Write the answer in Standard Form: __________ times larger

User Hearns
by
5.7k points

1 Answer

5 votes

Answer:

2.0 x
10^(1)

Explanation:

1. length = 3.2 x
10^(5) m

width = 1.6 x
10^(4) m

Area of a rectangle = length x width

= (3.2 x
10^(5)) x (1.6 x
10^(4))

= 5.12 x
10^(9)
m^(2)

2. length = 1.28 x
10^(7) m

width = 8 x
10^(3) m

Area of a rectangle = length x width

= (1.28 x
10^(7)) x (8 x
10^(3))

= 1.024 x
10^(11)
m^(2)


(Area of rectangle 2)/(Area of rectangle 1) =
(1.024*10^(11) )/(5.12*10^(9) )

= 20

= 2.0 x
10^(1)

Thus,

The area of rectangle 2 is 2.0 x
10^(1) times greater than the area of rectangle 1.

User Deinocheirus
by
6.3k points