Question

Given the point and slope write the equation of the line (-4, 0); slope = 1/2

Answer 1

The equation of the line will be:

`y=(1)/(2)x+2`

Explanation:

Given the point

• (-4, 0)

• slope = m = 1/2

As the equation of a line in slope-intercept form is

`y-y_1=m\left(x-x_1\right)`

• where m is the slope

substituting the values m = 1/2 and the point (-4, 0)

`y-y_1=m\left(x-x_1\right)`

`y-0=(1)/(2)\left(x-\left(-4\right)\right)`

`y=(1)/(2)\left(x-\left(-4\right)\right)`

`y=(1)/(2)\left(x+4\right)`

`y=(1)/(2)x+(4)/(2)`

`y=(1)/(2)x+2`

Therefore, the equation of the line will be:

`y=(1)/(2)x+2`