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An eraser is thrown upward with an initial velocity of 5.0m/s. The eraser’s velocity after 7.0 second is

1 Answer

4 votes

Answer:

-63.6m/s

Step-by-step explanation:

Given parameters:

Initial velocity = 5m/s

Time of flight = 7s

Unknown:

Velocity of the eraser after 7s = ?

Solution:

To solve this problem, we have to use the right motion equation which is given below;

v = u - gt

v is the final velocity

u is the initial velocity

g is the acceleration due to gravity = 9.8m/s²

t is the time taken;

Now insert the parameters and solve for v;

v = 5 - (9.8 x 7)

v = -63.6m/s

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