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1 vote
This is a simultaneous equation and I need help
5x+3y=27
2x+y=10

User Suvonkar
by
4.2k points

2 Answers

3 votes

Answer:

(3, 4 )

Explanation:

5x + 3y = 27 → (1)

2x + y = 10 ( subtract 2x from both sides )

y = 10 - 2x → (2)

substitute y = 10 - 2x into (1)

5x + 3(10 - 2x) = 27

5x + 30 - 6x = 27

- x + 30 = 27 ( subtract 30 from both sides )

- x = - 3 ( multiply both sides by - 1 )

x = 3

substitute x = 3 into (2)

y = 10 - 2(3) = 10 - 6 = 4

solution is (3, 4 )

User Maksym Govorischev
by
4.0k points
8 votes
Your answer is:

X = 3
Y = 4

Ordered pair form: (3,4)
User Filiph
by
4.4k points