Question

A 6.0 kg object is pushed with a force of 12 N. If the mass of the object is cut in half to 3.0 kg, what happens to the acceleration if the force remains constant?

Answer 1

aceleration doubles

Step-by-step explanation:

From Newton's secon law, one has

F=m*a

where F is the force, m the mass and a the aceleration.

In general, if m becomes m/2, in order to have the same force,

the acceleration must be doubled:

`F=m*a=(m)/(2) (2*a)`

In our particular case,

`12=6*a=(6)/(2) (2*a)\\12=3(2*a)`