Answer:
0.56 mL
Step-by-step explanation:
Methane gas and chlorine gas react to form hydrogen chloride gas and carbon tetrachloride gas. What volume of carbon tetrachloride would be produced by this reaction if 1.1 mL of chlorine were consumed.
Step 1: Write the balanced equation
CH₄(g) + 2 Cl₂(g) → CCl₄(g) + 4 HCl (g)
Step 2: Calculate the moles corresponding to 1.1 mL of Cl₂
At standard temperature and pressure, 1 mole of a gas has a volume of 22.4 L.
1.1 × 10⁻³ L × 1 mol/22.4 L = 4.9 × 10⁻⁵ mol
Step 3: Calculate the moles of CCl₄ formed from 4.9 × 10⁻⁵ moles of Cl₂
The molar ratio of Cl₂ to CCl₄ is 2:1. The moles of CCl₄ are 1/2 × 4.9 × 10⁻⁵ mol = 2.5 × 10⁻⁵ mol.
Step 4: Calculate the volume corresponding to 2.5 × 10⁻⁵ moles of CCl₄
At standard temperature and pressure, 1 mole of a gas has a volume of 22.4 L.
2.5 × 10⁻⁵ mol × 22.4 L/mol = 5.6 × 10⁻⁴ L = 0.56 mL